What are the solutions to the equation 0=x^3-4x^2-25x+100 ?

The solutions to the equation 0=x^3-4x^2-25x+100 are x=4,x=-5,x=5

Find the zeros of 0=x^3-4x^2-25x+100

The zeros of 0=x^3-4x^2-25x+100 are x=4,x=-5,x=5

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0 = x^{3} - 4 x^{2} - 25 x + 100

x = 4, x = - 5, x = 5

Solution steps

0 = x^{3} - 4 x^{2} - 25 x + 100

Switch sides

x^{3} - 4 x^{2} - 25 x + 100 = 0

Factor

x^{3} - 4 x^{2} - 25 x + 100 : (x - 4) (x + 5) (x - 5)

(x - 4) (x + 5) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 = 0 or x + 5 = 0 or x - 5 = 0

Solve

x - 4 = 0 : x = 4

Solve

x + 5 = 0 : x = - 5

Solve

x - 5 = 0 : x = 5

The solutions are

x = 4, x = - 5, x = 5

x^{3} + 2 x^{2} - 10 x = 0

r^{3} + 2 r^{2} + r = 0

x^{3} - 45 x = 4 x^{2}

- x^{4} + x^{2} - 4 x - 8 = 0

(3 - x) x^{2} = 0

What are the solutions to the equation 0=x^3-4x^2-25x+100 ?
The solutions to the equation 0=x^3-4x^2-25x+100 are x=4,x=-5,x=5
Find the zeros of 0=x^3-4x^2-25x+100
The zeros of 0=x^3-4x^2-25x+100 are x=4,x=-5,x=5