What are the solutions to the equation 4x(x^2-2)=0 ?

The solutions to the equation 4x(x^2-2)=0 are x=0,x=-sqrt(2),x=sqrt(2)

Find the zeros of 4x(x^2-2)=0

The zeros of 4x(x^2-2)=0 are x=0,x=-sqrt(2),x=sqrt(2)

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4 x (x^{2} - 2) = 0

x = 0, x = - 2, x = 2

Decimal Notation

x = 0, x = - 1.41421 \dots, x = 1.41421 \dots

Solution steps

4 x (x^{2} - 2) = 0

Factor

4 x (x^{2} - 2) : 4 x (x + 2) (x - 2)

4 x (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 2 = 0 or x - 2 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = - 2, x = 2

x^{3} + x^{2} - 3 x - 6 = 0

(x + 1)^{4} = 0

49 x^{4} - 175 x^{2} + 144 = 0

12 x^{3} - 20 x^{2} - 5 x + 1 = 0

4 x^{4} - 125 x^{2} + 625 = 0

What are the solutions to the equation 4x(x^2-2)=0 ?
The solutions to the equation 4x(x^2-2)=0 are x=0,x=-sqrt(2),x=sqrt(2)
Find the zeros of 4x(x^2-2)=0
The zeros of 4x(x^2-2)=0 are x=0,x=-sqrt(2),x=sqrt(2)