What are the solutions to the equation 9x^3-27x^2-25x+75=0 ?

The solutions to the equation 9x^3-27x^2-25x+75=0 are x=3,x=-5/3 ,x= 5/3

Find the zeros of 9x^3-27x^2-25x+75=0

The zeros of 9x^3-27x^2-25x+75=0 are x=3,x=-5/3 ,x= 5/3

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9 x^{3} - 27 x^{2} - 25 x + 75 = 0

x = 3, x = - \frac{5}{3}, x = \frac{5}{3}

Solution steps

9 x^{3} - 27 x^{2} - 25 x + 75 = 0

Factor

9 x^{3} - 27 x^{2} - 25 x + 75 : (x - 3) (3 x + 5) (3 x - 5)

(x - 3) (3 x + 5) (3 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or 3 x + 5 = 0 or 3 x - 5 = 0

Solve

x - 3 = 0 : x = 3

Solve

3 x + 5 = 0 : x = - \frac{5}{3}

Solve

3 x - 5 = 0 : x = \frac{5}{3}

The solutions are

x = 3, x = - \frac{5}{3}, x = \frac{5}{3}

- 34 x^{3} - 21 x^{2} - 30 x = 0

(3 p - 4)^{6} = 64

x^{3} - x = 6

x + 1. 5^{2} + 9 x^{4} = 0

x^{5} = 125

What are the solutions to the equation 9x^3-27x^2-25x+75=0 ?
The solutions to the equation 9x^3-27x^2-25x+75=0 are x=3,x=-5/3 ,x= 5/3
Find the zeros of 9x^3-27x^2-25x+75=0
The zeros of 9x^3-27x^2-25x+75=0 are x=3,x=-5/3 ,x= 5/3