What are the solutions to the equation 4x^4+7x^2-36=0 ?

The solutions to the equation 4x^4+7x^2-36=0 are x= 3/2 ,x=-3/2 ,x=2i,x=-2i

Find the zeros of 4x^4+7x^2-36=0

The zeros of 4x^4+7x^2-36=0 are x= 3/2 ,x=-3/2 ,x=2i,x=-2i

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4 x^{4} + 7 x^{2} - 36 = 0

x = \frac{3}{2}, x = - \frac{3}{2}, x = 2 i, x = - 2 i

Solution steps

4 x^{4} + 7 x^{2} - 36 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

4 u^{2} + 7 u - 36 = 0

Solve

4 u^{2} + 7 u - 36 = 0 : u = \frac{9}{4}, u = - 4

u = \frac{9}{4}, u = - 4

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = \frac{9}{4} : x = \frac{3}{2}, x = - \frac{3}{2}

Solve

x^{2} = - 4 : x = 2 i, x = - 2 i

The solutions are

x = \frac{3}{2}, x = - \frac{3}{2}, x = 2 i, x = - 2 i

x^{3} + 3 = 57

x^{4} - 6 x^{3} + 11 x^{2} - 8 x + 2 = 0

x^{4} - 3 x^{2} - 70 = 0

- 10 n^{3} - 15 n^{4} = 5 n^{3}

x^{8} - x^{6} - 2 x^{2} + 2 = 0

What are the solutions to the equation 4x^4+7x^2-36=0 ?
The solutions to the equation 4x^4+7x^2-36=0 are x= 3/2 ,x=-3/2 ,x=2i,x=-2i
Find the zeros of 4x^4+7x^2-36=0
The zeros of 4x^4+7x^2-36=0 are x= 3/2 ,x=-3/2 ,x=2i,x=-2i