What are the solutions to the equation 20x^2-32x-2x^3=0 ?

The solutions to the equation 20x^2-32x-2x^3=0 are x=0,x=2,x=8

Find the zeros of 20x^2-32x-2x^3=0

The zeros of 20x^2-32x-2x^3=0 are x=0,x=2,x=8

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20 x^{2} - 32 x - 2 x^{3} = 0

x = 0, x = 2, x = 8

Solution steps

20 x^{2} - 32 x - 2 x^{3} = 0

Factor

20 x^{2} - 32 x - 2 x^{3} : - 2 x (x - 2) (x - 8)

- 2 x (x - 2) (x - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 2 = 0 or x - 8 = 0

Solve

x - 2 = 0 : x = 2

Solve

x - 8 = 0 : x = 8

The solutions are

x = 0, x = 2, x = 8

(x + 4)^{3} - 9 x = 36

(1 - x)^{3} = x^{2} + x

x^{3} + x + 6 = 0

3 x^{3} + 9 x^{2} - 210 x = 0

(- x - 3)^{3} = 0

What are the solutions to the equation 20x^2-32x-2x^3=0 ?
The solutions to the equation 20x^2-32x-2x^3=0 are x=0,x=2,x=8
Find the zeros of 20x^2-32x-2x^3=0
The zeros of 20x^2-32x-2x^3=0 are x=0,x=2,x=8