What are the solutions to the equation x^3-4x^2+2x+3=0 ?

The solutions to the equation x^3-4x^2+2x+3=0 are x=3,x=(1+sqrt(5))/2 ,x=(1-sqrt(5))/2

Find the zeros of x^3-4x^2+2x+3=0

The zeros of x^3-4x^2+2x+3=0 are x=3,x=(1+sqrt(5))/2 ,x=(1-sqrt(5))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{3} - 4 x^{2} + 2 x + 3 = 0

x = 3, x = \frac{1 + 5}{2}, x = \frac{1 - 5}{2}

Solution steps

x^{3} - 4 x^{2} + 2 x + 3 = 0

Factor

x^{3} - 4 x^{2} + 2 x + 3 : (x - 3) (x^{2} - x - 1)

(x - 3) (x^{2} - x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x^{2} - x - 1 = 0

Solve

x - 3 = 0 : x = 3

Solve

x^{2} - x - 1 = 0 : x = \frac{1 + 5}{2}, x = \frac{1 - 5}{2}

The solutions are

x = 3, x = \frac{1 + 5}{2}, x = \frac{1 - 5}{2}

2 x^{3} + x^{2} + x + 1 = 0

h, 5 h (h^{2} + 12) = 68

- 3 x^{5} + 5 x^{3} = 0

524442 = 411536 (1 + x)^{14}

n^{3} = \frac{27}{343}

What are the solutions to the equation x^3-4x^2+2x+3=0 ?
The solutions to the equation x^3-4x^2+2x+3=0 are x=3,x=(1+sqrt(5))/2 ,x=(1-sqrt(5))/2
Find the zeros of x^3-4x^2+2x+3=0
The zeros of x^3-4x^2+2x+3=0 are x=3,x=(1+sqrt(5))/2 ,x=(1-sqrt(5))/2