What are the solutions to the equation -y^3+5y^2-7y+3=0 ?

The solutions to the equation -y^3+5y^2-7y+3=0 are y=1,y=3

Find the zeros of -y^3+5y^2-7y+3=0

The zeros of -y^3+5y^2-7y+3=0 are y=1,y=3

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- y^{3} + 5 y^{2} - 7 y + 3 = 0

y = 1, y = 3

Solution steps

- y^{3} + 5 y^{2} - 7 y + 3 = 0

Factor

- y^{3} + 5 y^{2} - 7 y + 3 : - (y - 1)^{2} (y - 3)

- (y - 1)^{2} (y - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y - 1 = 0 or y - 3 = 0

Solve

y - 1 = 0 : y = 1

Solve

y - 3 = 0 : y = 3

The solutions are

y = 1, y = 3

z^{3} = 1 + 3 i

3 x^{3} + x - 1 = 0

- 8 = p^{3}

x, f = 4 x^{3} + 2

5 x^{3} + 11 x^{2} + 7 x + 1 = 0

What are the solutions to the equation -y^3+5y^2-7y+3=0 ?
The solutions to the equation -y^3+5y^2-7y+3=0 are y=1,y=3
Find the zeros of -y^3+5y^2-7y+3=0
The zeros of -y^3+5y^2-7y+3=0 are y=1,y=3