What are the solutions to the equation x^4-x^3-2x^2=0 ?

The solutions to the equation x^4-x^3-2x^2=0 are x=0,x=-1,x=2

Find the zeros of x^4-x^3-2x^2=0

The zeros of x^4-x^3-2x^2=0 are x=0,x=-1,x=2

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x^{4} - x^{3} - 2 x^{2} = 0

x = 0, x = - 1, x = 2

Solution steps

x^{4} - x^{3} - 2 x^{2} = 0

Factor

x^{4} - x^{3} - 2 x^{2} : x^{2} (x + 1) (x - 2)

x^{2} (x + 1) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 1 = 0 or x - 2 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = - 1, x = 2

2 x^{4} - 3 x^{3} + 12 x^{2} - 16 x + 5 = 0

2 x^{3} = 48

x (2 x + 3) (4 x^{2} - 81) = 0

x^{9} = 2

y^{4} + y^{3} + y^{2} = 0

What are the solutions to the equation x^4-x^3-2x^2=0 ?
The solutions to the equation x^4-x^3-2x^2=0 are x=0,x=-1,x=2
Find the zeros of x^4-x^3-2x^2=0
The zeros of x^4-x^3-2x^2=0 are x=0,x=-1,x=2