What are the solutions to the equation x^4-4x^3+2x^2+4x-3=0 ?

The solutions to the equation x^4-4x^3+2x^2+4x-3=0 are x=-1,x=1,x=3

Find the zeros of x^4-4x^3+2x^2+4x-3=0

The zeros of x^4-4x^3+2x^2+4x-3=0 are x=-1,x=1,x=3

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x^{4} - 4 x^{3} + 2 x^{2} + 4 x - 3 = 0

x = - 1, x = 1, x = 3

Solution steps

x^{4} - 4 x^{3} + 2 x^{2} + 4 x - 3 = 0

Factor

x^{4} - 4 x^{3} + 2 x^{2} + 4 x - 3 : (x + 1) (x - 1)^{2} (x - 3)

(x + 1) (x - 1)^{2} (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 1 = 0 or x - 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

Solve

x - 3 = 0 : x = 3

The solutions are

x = - 1, x = 1, x = 3

80 = - 0.001 x^{3} + 0.18 x^{2} + 60

1 - z + z^{2} - z^{3} = 0

50 + 2 (\frac{x - 2}{4})^{3} = 300

z^{3} = \frac{1}{8 i}

x^{3} - 8 x^{2} + 4 x = 32

What are the solutions to the equation x^4-4x^3+2x^2+4x-3=0 ?
The solutions to the equation x^4-4x^3+2x^2+4x-3=0 are x=-1,x=1,x=3
Find the zeros of x^4-4x^3+2x^2+4x-3=0
The zeros of x^4-4x^3+2x^2+4x-3=0 are x=-1,x=1,x=3