What are the solutions to the equation 8x(x^2-1)^3=0 ?

The solutions to the equation 8x(x^2-1)^3=0 are x=0,x=-1,x=1

Find the zeros of 8x(x^2-1)^3=0

The zeros of 8x(x^2-1)^3=0 are x=0,x=-1,x=1

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8 x (x^{2} - 1)^{3} = 0

x = 0, x = - 1, x = 1

Solution steps

8 x (x^{2} - 1)^{3} = 0

Factor

8 x (x^{2} - 1)^{3} : 8 x (x + 1)^{3} (x - 1)^{3}

8 x (x + 1)^{3} (x - 1)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 1 = 0 or x - 1 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = 0, x = - 1, x = 1

0 = y^{2} - y^{3}

x^{3} + 2 x - 1 = 2

t^{3} = 8

x^{3} - 8 x + 8 = 0

x^{3} - 3 x^{2} = (x - 3) (x + 20)

What are the solutions to the equation 8x(x^2-1)^3=0 ?
The solutions to the equation 8x(x^2-1)^3=0 are x=0,x=-1,x=1
Find the zeros of 8x(x^2-1)^3=0
The zeros of 8x(x^2-1)^3=0 are x=0,x=-1,x=1