What are the solutions to the equation -0.2x^3+x+4=0 ?

The solutions to the equation -0.2x^3+x+4=0 are x\approx 3.32020…

Find the zeros of -0.2x^3+x+4=0

The zeros of -0.2x^3+x+4=0 are x\approx 3.32020…

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- 0.2 x^{3} + x + 4 = 0

x \approx 3.32020 \dots

Solution steps

- 0.2 x^{3} + x + 4 = 0

Multiply both sides by

10

- 2 x^{3} + 10 x + 40 = 0

Find one solution for

- 2 x^{3} + 10 x + 40 = 0

using Newton-Raphson:

x \approx 3.32020 \dots

Apply long division:

\frac{- 2 x ^{3} + 10 x + 40}{x - 3.32020 \dots} = - 2 x^{2} - 6.64040 \dots x - 12.04746 \dots

- 2 x^{2} - 6.64040 \dots x - 12.04746 \dots \approx 0

Find one solution for

- 2 x^{2} - 6.64040 \dots x - 12.04746 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx 3.32020 \dots

x^{3} - 17 x + 29 = 0

x - \cdot x^{4} = x^{12}

x^{3} - 13 x^{2} = 0

m^{5} - 2 m^{4} - m + 2 = 0

x^{3} - 8 x + 6 = 0

What are the solutions to the equation -0.2x^3+x+4=0 ?
The solutions to the equation -0.2x^3+x+4=0 are x\approx 3.32020…
Find the zeros of -0.2x^3+x+4=0
The zeros of -0.2x^3+x+4=0 are x\approx 3.32020…