What are the solutions to the equation (1+x)^5=4 ?

The solutions to the equation (1+x)^5=4 are x=\sqrt[5]{4}-1

Find the zeros of (1+x)^5=4

The zeros of (1+x)^5=4 are x=\sqrt[5]{4}-1

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(1 + x)^{5} = 4

Decimal Notation

x = 0.31950 \dots

Solution steps

(1 + x)^{5} = 4

For

(g (x))^{n} = f (a)

, n is odd, the solution is

Solve

The solution is

\frac{8}{125} = x^{3}

x^{3} - 3 x - 2.1 = 0

9 x^{3} = 7 x^{2}

x^{3} + 2 x - 5 = 0

(y^{2} - 8)^{2} + 4 (y^{2} - 8) - 5 = 0

What are the solutions to the equation (1+x)^5=4 ?
The solutions to the equation (1+x)^5=4 are x=\sqrt[5]{4}-1
Find the zeros of (1+x)^5=4
The zeros of (1+x)^5=4 are x=\sqrt[5]{4}-1