What are the solutions to the equation 2x^3-4x=0 ?

The solutions to the equation 2x^3-4x=0 are x=0,x=-sqrt(2),x=sqrt(2)

Find the zeros of 2x^3-4x=0

The zeros of 2x^3-4x=0 are x=0,x=-sqrt(2),x=sqrt(2)

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2 x^{3} - 4 x = 0

x = 0, x = - 2, x = 2

Decimal Notation

x = 0, x = - 1.41421 \dots, x = 1.41421 \dots

Solution steps

2 x^{3} - 4 x = 0

Factor

2 x^{3} - 4 x : 2 x (x + 2) (x - 2)

2 x (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 2 = 0 or x - 2 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = - 2, x = 2

z, z^{3} = 1

u^{3} + u^{2} + 1 = 0

x^{3} - 14 x^{2} + 40 x = 0

31 = x^{4}

x^{3} + x^{2} = 150

What are the solutions to the equation 2x^3-4x=0 ?
The solutions to the equation 2x^3-4x=0 are x=0,x=-sqrt(2),x=sqrt(2)
Find the zeros of 2x^3-4x=0
The zeros of 2x^3-4x=0 are x=0,x=-sqrt(2),x=sqrt(2)