What are the solutions to the equation 7y^3+17y^2=12y ?

The solutions to the equation 7y^3+17y^2=12y are y=0,y= 4/7 ,y=-3

Find the zeros of 7y^3+17y^2=12y

The zeros of 7y^3+17y^2=12y are y=0,y= 4/7 ,y=-3

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7 y^{3} + 17 y^{2} = 12 y

y = 0, y = \frac{4}{7}, y = - 3

Decimal Notation

y = 0, y = 0.57142 \dots, y = - 3

Solution steps

7 y^{3} + 17 y^{2} = 12 y

Move

12 y

to the left side

7 y^{3} + 17 y^{2} - 12 y = 0

Factor

7 y^{3} + 17 y^{2} - 12 y : y (7 y - 4) (y + 3)

y (7 y - 4) (y + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or 7 y - 4 = 0 or y + 3 = 0

Solve

7 y - 4 = 0 : y = \frac{4}{7}

Solve

y + 3 = 0 : y = - 3

The solutions are

y = 0, y = \frac{4}{7}, y = - 3

x, x^{3} + (y - 1)^{2} = 9

a, y = a^{3} + b^{2}

2 x^{3} - 3 x^{2} = 0

y^{4} + 12 y^{2} - 64 = 0

15 + x^{3} = 4 x^{2} + 15

What are the solutions to the equation 7y^3+17y^2=12y ?
The solutions to the equation 7y^3+17y^2=12y are y=0,y= 4/7 ,y=-3
Find the zeros of 7y^3+17y^2=12y
The zeros of 7y^3+17y^2=12y are y=0,y= 4/7 ,y=-3