What are the solutions to the equation 0=-(x^3)/3+x^2 ?

The solutions to the equation 0=-(x^3)/3+x^2 are x=0,x=3

Find the zeros of 0=-(x^3)/3+x^2

The zeros of 0=-(x^3)/3+x^2 are x=0,x=3

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0 = - \frac{x ^{3}}{3} + x^{2}

x = 0, x = 3

Solution steps

0 = - \frac{x ^{3}}{3} + x^{2}

Switch sides

- \frac{x ^{3}}{3} + x^{2} = 0

Factor

- \frac{x ^{3}}{3} + x^{2} : - x^{2} (\frac{x}{3} - 1)

- x^{2} (\frac{x}{3} - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or \frac{x}{3} - 1 = 0

Solve

\frac{x}{3} - 1 = 0 : x = 3

The solutions are

x = 0, x = 3

4 x^{2} - 2 x^{3} - 2 x^{3} - x^{4} = 0

3 x^{3} + x^{2} - 38 x + 24 = 0

x^{3} + 3 x^{2} = - x^{2} + 3 x + 7

3018 = x^{4} - x^{3} - 7 x^{2} + 9 x

- x^{3} + 6 x^{2} - 12 x + 6 = 0

What are the solutions to the equation 0=-(x^3)/3+x^2 ?
The solutions to the equation 0=-(x^3)/3+x^2 are x=0,x=3
Find the zeros of 0=-(x^3)/3+x^2
The zeros of 0=-(x^3)/3+x^2 are x=0,x=3