What are the solutions to the equation 7x^3+3x^2-29x+11=0 ?

The solutions to the equation 7x^3+3x^2-29x+11=0 are x= 11/7 ,x=-1+sqrt(2),x=-1-sqrt(2)

Find the zeros of 7x^3+3x^2-29x+11=0

The zeros of 7x^3+3x^2-29x+11=0 are x= 11/7 ,x=-1+sqrt(2),x=-1-sqrt(2)

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7 x^{3} + 3 x^{2} - 29 x + 11 = 0

x = \frac{11}{7}, x = - 1 + 2, x = - 1 - 2

Decimal Notation

x = 1.57142 \dots, x = 0.41421 \dots, x = - 2.41421 \dots

Solution steps

7 x^{3} + 3 x^{2} - 29 x + 11 = 0

Factor

7 x^{3} + 3 x^{2} - 29 x + 11 : (7 x - 11) (x^{2} + 2 x - 1)

(7 x - 11) (x^{2} + 2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

7 x - 11 = 0 or x^{2} + 2 x - 1 = 0

Solve

7 x - 11 = 0 : x = \frac{11}{7}

Solve

x^{2} + 2 x - 1 = 0 : x = - 1 + 2, x = - 1 - 2

The solutions are

x = \frac{11}{7}, x = - 1 + 2, x = - 1 - 2

- x^{3} + 5 x^{2} - 4 x = 0

x^{3} - 12 x^{2} - 56 x + 552 = 0

11 x^{10} = 15 x - 9

x^{6} - 8 x^{3} + 1 = 0

x^{3} - x^{2} - 54 x + 123 = 0

What are the solutions to the equation 7x^3+3x^2-29x+11=0 ?
The solutions to the equation 7x^3+3x^2-29x+11=0 are x= 11/7 ,x=-1+sqrt(2),x=-1-sqrt(2)
Find the zeros of 7x^3+3x^2-29x+11=0
The zeros of 7x^3+3x^2-29x+11=0 are x= 11/7 ,x=-1+sqrt(2),x=-1-sqrt(2)