What are the solutions to the equation (x-5)^4-(5-x)^2=0 ?

The solutions to the equation (x-5)^4-(5-x)^2=0 are x=5,x=4,x=6

Find the zeros of (x-5)^4-(5-x)^2=0

The zeros of (x-5)^4-(5-x)^2=0 are x=5,x=4,x=6

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(x - 5)^{4} - (5 - x)^{2} = 0

x = 5, x = 4, x = 6

Solution steps

(x - 5)^{4} - (5 - x)^{2} = 0

Factor

(x - 5)^{4} - (5 - x)^{2} : (x - 5)^{2} (x - 4) (x - 6)

(x - 5)^{2} (x - 4) (x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 5 = 0 or x - 4 = 0 or x - 6 = 0

Solve

x - 5 = 0 : x = 5

Solve

x - 4 = 0 : x = 4

Solve

x - 6 = 0 : x = 6

The solutions are

x = 5, x = 4, x = 6

x^{4} - 5 x^{2} = 4

t^{3} + 2 t = 400

9 x - x^{3} = 0

12 x^{5} = 20 x^{4} + 8 x^{2} - 16

5.3 \cdot 1 0^{- 9} = (y) (2 y)^{2}

What are the solutions to the equation (x-5)^4-(5-x)^2=0 ?
The solutions to the equation (x-5)^4-(5-x)^2=0 are x=5,x=4,x=6
Find the zeros of (x-5)^4-(5-x)^2=0
The zeros of (x-5)^4-(5-x)^2=0 are x=5,x=4,x=6