What are the solutions to the equation (1-y)(3-y)(6-y)=18 ?

The solutions to the equation (1-y)(3-y)(6-y)=18 are y=0,y=5+sqrt(2)i,y=5-sqrt(2)i

Find the zeros of (1-y)(3-y)(6-y)=18

The zeros of (1-y)(3-y)(6-y)=18 are y=0,y=5+sqrt(2)i,y=5-sqrt(2)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(1 - y) (3 - y) (6 - y) = 18

y = 0, y = 5 + 2 i, y = 5 - 2 i

Solution steps

(1 - y) (3 - y) (6 - y) = 18

Expand

(1 - y) (3 - y) (6 - y) : 18 - 27 y + 10 y^{2} - y^{3}

18 - 27 y + 10 y^{2} - y^{3} = 18

Move

18

to the left side

- y^{3} + 10 y^{2} - 27 y = 0

Factor

- y^{3} + 10 y^{2} - 27 y : - y (y^{2} - 10 y + 27)

- y (y^{2} - 10 y + 27) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or y^{2} - 10 y + 27 = 0

Solve

y^{2} - 10 y + 27 = 0 : y = 5 + 2 i, y = 5 - 2 i

The solutions are

y = 0, y = 5 + 2 i, y = 5 - 2 i

(s^{3} - s^{2} + s - 1) = s^{2} + 3 s + 4

8 x^{4} = 6 x^{3}

x^{3} + 7 x^{2} + 2 x + 14 = 0

x^{4} - 16 x^{3} + 76 x^{2} - 96 x + 16 = 0

3 x^{3} + x = 0

What are the solutions to the equation (1-y)(3-y)(6-y)=18 ?
The solutions to the equation (1-y)(3-y)(6-y)=18 are y=0,y=5+sqrt(2)i,y=5-sqrt(2)i
Find the zeros of (1-y)(3-y)(6-y)=18
The zeros of (1-y)(3-y)(6-y)=18 are y=0,y=5+sqrt(2)i,y=5-sqrt(2)i