What are the solutions to the equation u^2-13u+36=0 ?

The solutions to the equation u^2-13u+36=0 are u=9,u=4

Find the zeros of u^2-13u+36=0

The zeros of u^2-13u+36=0 are u=9,u=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

u^{2} - 13 u + 36 = 0

u = 9, u = 4

Solution steps

u^{2} - 13 u + 36 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot 36 = 5

u_{1, 2} = \frac{- ( - 13 ) \pm 5}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 13 ) + 5}{2 \cdot 1}, u_{2} = \frac{- ( - 13 ) - 5}{2 \cdot 1}

u = \frac{- ( - 13 ) + 5}{2 \cdot 1} : 9

u = \frac{- ( - 13 ) - 5}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

u = 9, u = 4

\frac{x + 1}{5} - \frac{4 x + 2}{3} = \frac{x - 1}{6}

18 x^{2} + 114 x - 84

- 80736.75 x + 132.9 x^{2} + 607.5 = 0

6 x - 8 + 2 x - 5 = 7 - 2 x

5 x^{2} - 6 x + 4 = 0

What are the solutions to the equation u^2-13u+36=0 ?
The solutions to the equation u^2-13u+36=0 are u=9,u=4
Find the zeros of u^2-13u+36=0
The zeros of u^2-13u+36=0 are u=9,u=4