What are the solutions to the equation (x^3+3x^2)-(9x+27)=0 ?

The solutions to the equation (x^3+3x^2)-(9x+27)=0 are x=-3,x=3

Find the zeros of (x^3+3x^2)-(9x+27)=0

The zeros of (x^3+3x^2)-(9x+27)=0 are x=-3,x=3

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(x^{3} + 3 x^{2}) - (9 x + 27) = 0

x = - 3, x = 3

Solution steps

(x^{3} + 3 x^{2}) - (9 x + 27) = 0

Factor

(x^{3} + 3 x^{2}) - (9 x + 27) : (x + 3)^{2} (x - 3)

(x + 3)^{2} (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x - 3 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = - 3, x = 3

x^{3} - 37 x + 6 = 0

x, x^{4} x^{2} - 9 y^{2} = 36

x^{4} - 7 x^{2} - 30 = 0

x^{2} \cdot 4 x - 8 = 0

x^{4} - 6 x^{3} - 7 x^{2} + 54 x - 18 = 0

What are the solutions to the equation (x^3+3x^2)-(9x+27)=0 ?
The solutions to the equation (x^3+3x^2)-(9x+27)=0 are x=-3,x=3
Find the zeros of (x^3+3x^2)-(9x+27)=0
The zeros of (x^3+3x^2)-(9x+27)=0 are x=-3,x=3