What are the solutions to the equation 3x^3-5x+2=0 ?

The solutions to the equation 3x^3-5x+2=0 are x=1,x=(-3+sqrt(33))/6 ,x=(-3-sqrt(33))/6

Find the zeros of 3x^3-5x+2=0

The zeros of 3x^3-5x+2=0 are x=1,x=(-3+sqrt(33))/6 ,x=(-3-sqrt(33))/6

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3 x^{3} - 5 x + 2 = 0

x = 1, x = \frac{- 3 + 33}{6}, x = \frac{- 3 - 33}{6}

Decimal Notation

x = 1, x = 0.45742 \dots, x = - 1.45742 \dots

Solution steps

3 x^{3} - 5 x + 2 = 0

Factor

3 x^{3} - 5 x + 2 : (x - 1) (3 x^{2} + 3 x - 2)

(x - 1) (3 x^{2} + 3 x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 3 x^{2} + 3 x - 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

3 x^{2} + 3 x - 2 = 0 : x = \frac{- 3 + 33}{6}, x = \frac{- 3 - 33}{6}

The solutions are

x = 1, x = \frac{- 3 + 33}{6}, x = \frac{- 3 - 33}{6}

(3 x - 1)^{2} x (x - 3) = 1

z^{3} - 3 z - 3 = 0

- 2 (x + 2)^{3} - 8 = 0

x, f = x^{4} - 6 x^{2} + 6

x^{3} + 3 x^{2} + 7 x + 21 = 0

What are the solutions to the equation 3x^3-5x+2=0 ?
The solutions to the equation 3x^3-5x+2=0 are x=1,x=(-3+sqrt(33))/6 ,x=(-3-sqrt(33))/6
Find the zeros of 3x^3-5x+2=0
The zeros of 3x^3-5x+2=0 are x=1,x=(-3+sqrt(33))/6 ,x=(-3-sqrt(33))/6