What are the solutions to the equation 0=12x^3+12x^2-24x ?

The solutions to the equation 0=12x^3+12x^2-24x are x=0,x=1,x=-2

Find the zeros of 0=12x^3+12x^2-24x

The zeros of 0=12x^3+12x^2-24x are x=0,x=1,x=-2

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0 = 12 x^{3} + 12 x^{2} - 24 x

x = 0, x = 1, x = - 2

Solution steps

0 = 12 x^{3} + 12 x^{2} - 24 x

Switch sides

12 x^{3} + 12 x^{2} - 24 x = 0

Factor

12 x^{3} + 12 x^{2} - 24 x : 12 x (x - 1) (x + 2)

12 x (x - 1) (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 1 = 0 or x + 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 2 = 0 : x = - 2

The solutions are

x = 0, x = 1, x = - 2

0 = x (x^{2} - 3)

a^{6} = 58 + (6 - 1) - 7

x^{4} - 5 x^{2} + 3 = 0

2 x^{3} + 26 x^{2} + 84 x = 0

(x - 2)^{2} (x + 3) = 0

What are the solutions to the equation 0=12x^3+12x^2-24x ?
The solutions to the equation 0=12x^3+12x^2-24x are x=0,x=1,x=-2
Find the zeros of 0=12x^3+12x^2-24x
The zeros of 0=12x^3+12x^2-24x are x=0,x=1,x=-2