What are the solutions to the equation 3y^3-23y^2-8y=0 ?

The solutions to the equation 3y^3-23y^2-8y=0 are y=0,y=-1/3 ,y=8

Find the zeros of 3y^3-23y^2-8y=0

The zeros of 3y^3-23y^2-8y=0 are y=0,y=-1/3 ,y=8

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3 y^{3} - 23 y^{2} - 8 y = 0

y = 0, y = - \frac{1}{3}, y = 8

Decimal Notation

y = 0, y = - 0.33333 \dots, y = 8

Solution steps

3 y^{3} - 23 y^{2} - 8 y = 0

Factor

3 y^{3} - 23 y^{2} - 8 y : y (3 y + 1) (y - 8)

y (3 y + 1) (y - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or 3 y + 1 = 0 or y - 8 = 0

Solve

3 y + 1 = 0 : y = - \frac{1}{3}

Solve

y - 8 = 0 : y = 8

The solutions are

y = 0, y = - \frac{1}{3}, y = 8

x, x^{4} + y^{4} = 17

k^{3} = 216

2 y^{2} (y^{2} - 2) = 18 + y^{2}

2 x^{4} - 2 x^{3} + x^{2} + 3 x - 4 = 0

9 x^{4} + 8 0^{2} - 9 = 0

What are the solutions to the equation 3y^3-23y^2-8y=0 ?
The solutions to the equation 3y^3-23y^2-8y=0 are y=0,y=-1/3 ,y=8
Find the zeros of 3y^3-23y^2-8y=0
The zeros of 3y^3-23y^2-8y=0 are y=0,y=-1/3 ,y=8