What are the solutions to the equation 3x^3-5x^2+6x=0 ?

The solutions to the equation 3x^3-5x^2+6x=0 are x=0,x= 5/6+i(sqrt(47))/6 ,x= 5/6-i(sqrt(47))/6

Find the zeros of 3x^3-5x^2+6x=0

The zeros of 3x^3-5x^2+6x=0 are x=0,x= 5/6+i(sqrt(47))/6 ,x= 5/6-i(sqrt(47))/6

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3 x^{3} - 5 x^{2} + 6 x = 0

x = 0, x = \frac{5}{6} + i \frac{47}{6}, x = \frac{5}{6} - i \frac{47}{6}

Solution steps

3 x^{3} - 5 x^{2} + 6 x = 0

Factor

3 x^{3} - 5 x^{2} + 6 x : x (3 x^{2} - 5 x + 6)

x (3 x^{2} - 5 x + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 3 x^{2} - 5 x + 6 = 0

Solve

3 x^{2} - 5 x + 6 = 0 : x = \frac{5}{6} + i \frac{47}{6}, x = \frac{5}{6} - i \frac{47}{6}

The solutions are

x = 0, x = \frac{5}{6} + i \frac{47}{6}, x = \frac{5}{6} - i \frac{47}{6}

- x^{3} - 5 x^{2} + 6 x + 32 = 0

x^{3} - x - 12 = 0

x^{4} - 8 x^{3} + 24 x^{2} - 32 x = 0

x^{3} - 10 x + 21 = 0

x^{4} - 12 x^{2} + 16 = 0

What are the solutions to the equation 3x^3-5x^2+6x=0 ?
The solutions to the equation 3x^3-5x^2+6x=0 are x=0,x= 5/6+i(sqrt(47))/6 ,x= 5/6-i(sqrt(47))/6
Find the zeros of 3x^3-5x^2+6x=0
The zeros of 3x^3-5x^2+6x=0 are x=0,x= 5/6+i(sqrt(47))/6 ,x= 5/6-i(sqrt(47))/6