What are the solutions to the equation (6x^2-x-2)(ax+9)=0,a\ne 0 ?

The solutions to the equation (6x^2-x-2)(ax+9)=0,a\ne 0 are x=-1/2 ,x= 2/3 ,x=-9/a ;\quad a\ne 0

Find the zeros of (6x^2-x-2)(ax+9)=0,a\ne 0

The zeros of (6x^2-x-2)(ax+9)=0,a\ne 0 are x=-1/2 ,x= 2/3 ,x=-9/a ;\quad a\ne 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(6 x^{2} - x - 2) (a x + 9) = 0, a \neq = 0

x = - \frac{1}{2}, x = \frac{2}{3}, x = - \frac{9}{a}; a \neq = 0

Decimal Notation

x = - 0.5, x = 0.66666 \dots

Solution steps

(6 x^{2} - x - 2) (a x + 9) = 0, a \neq = 0

Factor

(6 x^{2} - x - 2) (a x + 9) : (2 x + 1) (3 x - 2) (a x + 9)

(2 x + 1) (3 x - 2) (a x + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 1 = 0 or 3 x - 2 = 0 or a x + 9 = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

3 x - 2 = 0 : x = \frac{2}{3}

Solve

a x + 9 = 0 : x = - \frac{9}{a}; a \neq = 0

The solutions are

x = - \frac{1}{2}, x = \frac{2}{3}, x = - \frac{9}{a}; a \neq = 0

16 x^{3} + 64 x^{2} - 25 x - 100 = 0

2 x^{4} - 4 x^{2} + 1 = 0

(x - 3)^{4} - 30 = 0

x^{3} + 3 x^{2} + 2 x + 7 = 0

\frac{1}{2} x^{3} + 3 x - 4 = - 2

What are the solutions to the equation (6x^2-x-2)(ax+9)=0,a\ne 0 ?
The solutions to the equation (6x^2-x-2)(ax+9)=0,a\ne 0 are x=-1/2 ,x= 2/3 ,x=-9/a ;\quad a\ne 0
Find the zeros of (6x^2-x-2)(ax+9)=0,a\ne 0
The zeros of (6x^2-x-2)(ax+9)=0,a\ne 0 are x=-1/2 ,x= 2/3 ,x=-9/a ;\quad a\ne 0