What are the solutions to the equation y^4-13y^3=-42y^2 ?

The solutions to the equation y^4-13y^3=-42y^2 are y=0,y=6,y=7

Find the zeros of y^4-13y^3=-42y^2

The zeros of y^4-13y^3=-42y^2 are y=0,y=6,y=7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{4} - 13 y^{3} = - 42 y^{2}

y = 0, y = 6, y = 7

Solution steps

y^{4} - 13 y^{3} = - 42 y^{2}

Move

42 y^{2}

to the left side

y^{4} - 13 y^{3} + 42 y^{2} = 0

Factor

y^{4} - 13 y^{3} + 42 y^{2} : y^{2} (y - 6) (y - 7)

y^{2} (y - 6) (y - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or y - 6 = 0 or y - 7 = 0

Solve

y - 6 = 0 : y = 6

Solve

y - 7 = 0 : y = 7

The solutions are

y = 0, y = 6, y = 7

9 x = \frac{1}{4} x^{3}

- \frac{x ^{3}}{3} - x^{2} + 3 x + 10 = 0

(s^{2} + 17800 s + 39500000)^{2} = 0

t, (1 + t)^{5} = 1.2784

4 x^{4} + 65 x^{2} + 16 = 0

What are the solutions to the equation y^4-13y^3=-42y^2 ?
The solutions to the equation y^4-13y^3=-42y^2 are y=0,y=6,y=7
Find the zeros of y^4-13y^3=-42y^2
The zeros of y^4-13y^3=-42y^2 are y=0,y=6,y=7