What are the solutions to the equation 4x^3-(4x)/9 =0 ?

The solutions to the equation 4x^3-(4x)/9 =0 are x=0,x=-1/3 ,x= 1/3

Find the zeros of 4x^3-(4x)/9 =0

The zeros of 4x^3-(4x)/9 =0 are x=0,x=-1/3 ,x= 1/3

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4 x^{3} - \frac{4 x}{9} = 0

x = 0, x = - \frac{1}{3}, x = \frac{1}{3}

Decimal Notation

x = 0, x = - 0.33333 \dots, x = 0.33333 \dots

Solution steps

4 x^{3} - \frac{4 x}{9} = 0

Factor

4 x^{3} - \frac{4 x}{9} : x (2 x + \frac{2}{3}) (2 x - \frac{2}{3})

x (2 x + \frac{2}{3}) (2 x - \frac{2}{3}) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x + \frac{2}{3} = 0 or 2 x - \frac{2}{3} = 0

Solve

2 x + \frac{2}{3} = 0 : x = - \frac{1}{3}

Solve

2 x - \frac{2}{3} = 0 : x = \frac{1}{3}

The solutions are

x = 0, x = - \frac{1}{3}, x = \frac{1}{3}

q^{4} - 2 = 1

2 z (z + 3) (z + 5) = 0

32 x^{5} - 40 x^{3} + 10 x + 1 = 0

(2 x + 3) (2 x^{3}) = 0

D^{3} - D = 0

What are the solutions to the equation 4x^3-(4x)/9 =0 ?
The solutions to the equation 4x^3-(4x)/9 =0 are x=0,x=-1/3 ,x= 1/3
Find the zeros of 4x^3-(4x)/9 =0
The zeros of 4x^3-(4x)/9 =0 are x=0,x=-1/3 ,x= 1/3