What are the solutions to the equation x^4+4x^3+17x^2+36x+72=0 ?

The solutions to the equation x^4+4x^3+17x^2+36x+72=0 are No Solution for x\in\mathbb{R}

Find the zeros of x^4+4x^3+17x^2+36x+72=0

The zeros of x^4+4x^3+17x^2+36x+72=0 are No Solution for x\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{4} + 4 x^{3} + 17 x^{2} + 36 x + 72 = 0

No Solution for x \in R

Solution steps

x^{4} + 4 x^{3} + 17 x^{2} + 36 x + 72 = 0

Find one solution for

x^{4} + 4 x^{3} + 17 x^{2} + 36 x + 72 = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

No Solution for x \in R

x, y^{2} = x^{6}

1056 X^{3} - 55 X^{2} - 55 X - 1055 = 0

9 x^{4} + 85 x^{2} + 36 = 0

x, d u = x^{3} + 5

125 x^{3} - 64 = 0

What are the solutions to the equation x^4+4x^3+17x^2+36x+72=0 ?
The solutions to the equation x^4+4x^3+17x^2+36x+72=0 are No Solution for x\in\mathbb{R}
Find the zeros of x^4+4x^3+17x^2+36x+72=0
The zeros of x^4+4x^3+17x^2+36x+72=0 are No Solution for x\in\mathbb{R}