What are the solutions to the equation 8x^3+14x^2-5x-2=0 ?

The solutions to the equation 8x^3+14x^2-5x-2=0 are x=-2,x=-1/4 ,x= 1/2

Find the zeros of 8x^3+14x^2-5x-2=0

The zeros of 8x^3+14x^2-5x-2=0 are x=-2,x=-1/4 ,x= 1/2

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8 x^{3} + 14 x^{2} - 5 x - 2 = 0

x = - 2, x = - \frac{1}{4}, x = \frac{1}{2}

Decimal Notation

x = - 2, x = - 0.25, x = 0.5

Solution steps

8 x^{3} + 14 x^{2} - 5 x - 2 = 0

Factor

8 x^{3} + 14 x^{2} - 5 x - 2 : (x + 2) (4 x + 1) (2 x - 1)

(x + 2) (4 x + 1) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or 4 x + 1 = 0 or 2 x - 1 = 0

Solve

x + 2 = 0 : x = - 2

Solve

4 x + 1 = 0 : x = - \frac{1}{4}

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions are

x = - 2, x = - \frac{1}{4}, x = \frac{1}{2}

2 x^{4} + 9 x^{2} = 68

0 = 9 y - y^{3}

2.7 = (1 + x)^{6}

5 x^{3} + 2 x - 9 = 0

a, (4 baba + 7)^{2} = 0

What are the solutions to the equation 8x^3+14x^2-5x-2=0 ?
The solutions to the equation 8x^3+14x^2-5x-2=0 are x=-2,x=-1/4 ,x= 1/2
Find the zeros of 8x^3+14x^2-5x-2=0
The zeros of 8x^3+14x^2-5x-2=0 are x=-2,x=-1/4 ,x= 1/2