What are the solutions to the equation (r^3)/9 =3 ?

The solutions to the equation (r^3)/9 =3 are r=3,r=-3/2+(3sqrt(3))/2 i,r=-3/2-(3sqrt(3))/2 i

Find the zeros of (r^3)/9 =3

The zeros of (r^3)/9 =3 are r=3,r=-3/2+(3sqrt(3))/2 i,r=-3/2-(3sqrt(3))/2 i

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\frac{r ^{3}}{9} = 3

r = 3, r = - \frac{3}{2} + \frac{3 3}{2} i, r = - \frac{3}{2} - \frac{3 3}{2} i

Solution steps

\frac{r ^{3}}{9} = 3

Multiply both sides by

9

r^{3} = 27

For

x^{3} = f (a)

the solutions are

Simplify

r = 3, r = - \frac{3}{2} + \frac{3 3}{2} i, r = - \frac{3}{2} - \frac{3 3}{2} i

x^{4} = - 2 + 23 i

5 - x^{3} = x^{2} + 6

9 x^{3} - 54 x^{2} - x + 6 = 0

23.92 x^{3} + 66.53 x^{2} - 300 = 0

z^{4} + 7 z^{2} - 144 = 0

What are the solutions to the equation (r^3)/9 =3 ?
The solutions to the equation (r^3)/9 =3 are r=3,r=-3/2+(3sqrt(3))/2 i,r=-3/2-(3sqrt(3))/2 i
Find the zeros of (r^3)/9 =3
The zeros of (r^3)/9 =3 are r=3,r=-3/2+(3sqrt(3))/2 i,r=-3/2-(3sqrt(3))/2 i