What are the solutions to the equation 3x^5+27x^3=0 ?

The solutions to the equation 3x^5+27x^3=0 are x=0,x=3i,x=-3i

Find the zeros of 3x^5+27x^3=0

The zeros of 3x^5+27x^3=0 are x=0,x=3i,x=-3i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{5} + 27 x^{3} = 0

x = 0, x = 3 i, x = - 3 i

Solution steps

3 x^{5} + 27 x^{3} = 0

Factor

3 x^{5} + 27 x^{3} : 3 x^{3} (x^{2} + 9)

3 x^{3} (x^{2} + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} + 9 = 0

Solve

x^{2} + 9 = 0 : x = 3 i, x = - 3 i

The solutions are

x = 0, x = 3 i, x = - 3 i

x^{3} + 6 x^{2} + 9 x = - 3

s (s + 1) (s + 2) = 1

x^{4} + 3 x^{2} - 2 = 0

(4 - y^{2})^{2} = 0

(2 x + 5)^{6} = (1 - x)^{6}

What are the solutions to the equation 3x^5+27x^3=0 ?
The solutions to the equation 3x^5+27x^3=0 are x=0,x=3i,x=-3i
Find the zeros of 3x^5+27x^3=0
The zeros of 3x^5+27x^3=0 are x=0,x=3i,x=-3i