What are the solutions to the equation x(x+2)(x+4)=4 ?

The solutions to the equation x(x+2)(x+4)=4 are x\approx 0.38297…

Find the zeros of x(x+2)(x+4)=4

The zeros of x(x+2)(x+4)=4 are x\approx 0.38297…

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x (x + 2) (x + 4) = 4

x \approx 0.38297 \dots

Solution steps

x (x + 2) (x + 4) = 4

Expand

x (x + 2) (x + 4) : x^{3} + 6 x^{2} + 8 x

x^{3} + 6 x^{2} + 8 x = 4

Move

4

to the left side

x^{3} + 6 x^{2} + 8 x - 4 = 0

Find one solution for

x^{3} + 6 x^{2} + 8 x - 4 = 0

using Newton-Raphson:

x \approx 0.38297 \dots

Apply long division:

\frac{x ^{3} + 6 x ^{2} + 8 x - 4}{x - 0.38297 \dots} = x^{2} + 6.38297 \dots x + 10.44452 \dots

x^{2} + 6.38297 \dots x + 10.44452 \dots \approx 0

Find one solution for

x^{2} + 6.38297 \dots x + 10.44452 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx 0.38297 \dots

n^{4} - 5 n^{2} = - 4

x^{3} + 7 x^{2} + 25 x + 175 = 0

x (x - 8) (x - 4)^{2} = 225

z^{5} = - 2

4 x^{3} = 500

What are the solutions to the equation x(x+2)(x+4)=4 ?
The solutions to the equation x(x+2)(x+4)=4 are x\approx 0.38297…
Find the zeros of x(x+2)(x+4)=4
The zeros of x(x+2)(x+4)=4 are x\approx 0.38297…