What are the solutions to the equation d^3*1=512*1 ?

The solutions to the equation d^3*1=512*1 are d=8,d=-4+4sqrt(3)i,d=-4-4sqrt(3)i

Find the zeros of d^3*1=512*1

The zeros of d^3*1=512*1 are d=8,d=-4+4sqrt(3)i,d=-4-4sqrt(3)i

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d^{3} \cdot 1 = 512 \cdot 1

d = 8, d = - 4 + 43 i, d = - 4 - 43 i

Solution steps

d^{3} \cdot 1 = 512 \cdot 1

Multiply:

d^{3} \cdot 1 = d^{3}

d^{3} = 512 \cdot 1

Multiply the numbers:

512 \cdot 1 = 512

d^{3} = 512

For

x^{3} = f (a)

the solutions are

Simplify

d = 8, d = - 4 + 43 i, d = - 4 - 43 i

y^{3} + 6 y^{2} - 7 y = 8

x^{4} - 2 x^{2} - 35 = 0

x^{3} - 2 x^{2} - 2 x + 1 = 0

x^{9} + 3 = 11

6 x^{3} - 13 x^{2} + 4 = 0

What are the solutions to the equation d^3*1=512*1 ?
The solutions to the equation d^3*1=512*1 are d=8,d=-4+4sqrt(3)i,d=-4-4sqrt(3)i
Find the zeros of d^3*1=512*1
The zeros of d^3*1=512*1 are d=8,d=-4+4sqrt(3)i,d=-4-4sqrt(3)i