What are the solutions to the equation 5x^3-4x^2-80x+64=0 ?

The solutions to the equation 5x^3-4x^2-80x+64=0 are x= 4/5 ,x=-4,x=4

Find the zeros of 5x^3-4x^2-80x+64=0

The zeros of 5x^3-4x^2-80x+64=0 are x= 4/5 ,x=-4,x=4

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5 x^{3} - 4 x^{2} - 80 x + 64 = 0

x = \frac{4}{5}, x = - 4, x = 4

Decimal Notation

x = 0.8, x = - 4, x = 4

Solution steps

5 x^{3} - 4 x^{2} - 80 x + 64 = 0

Factor

5 x^{3} - 4 x^{2} - 80 x + 64 : (5 x - 4) (x + 4) (x - 4)

(5 x - 4) (x + 4) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 x - 4 = 0 or x + 4 = 0 or x - 4 = 0

Solve

5 x - 4 = 0 : x = \frac{4}{5}

Solve

x + 4 = 0 : x = - 4

Solve

x - 4 = 0 : x = 4

The solutions are

x = \frac{4}{5}, x = - 4, x = 4

9 x^{3} + 45 x^{2} - 16 x - 80 = 0

4 x^{3} - 48 x + 192 x^{2} = 0

z^{3} = 3 - i

5 X^{3} = - 45 X

2 x^{3} + 5 c - 3 = 0

What are the solutions to the equation 5x^3-4x^2-80x+64=0 ?
The solutions to the equation 5x^3-4x^2-80x+64=0 are x= 4/5 ,x=-4,x=4
Find the zeros of 5x^3-4x^2-80x+64=0
The zeros of 5x^3-4x^2-80x+64=0 are x= 4/5 ,x=-4,x=4