What are the solutions to the equation 3x^3+7x^2-33x-77=0 ?

The solutions to the equation 3x^3+7x^2-33x-77=0 are x=-7/3 ,x=-sqrt(11),x=sqrt(11)

Find the zeros of 3x^3+7x^2-33x-77=0

The zeros of 3x^3+7x^2-33x-77=0 are x=-7/3 ,x=-sqrt(11),x=sqrt(11)

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3 x^{3} + 7 x^{2} - 33 x - 77 = 0

x = - \frac{7}{3}, x = - 11, x = 11

Decimal Notation

x = - 2.33333 \dots, x = - 3.31662 \dots, x = 3.31662 \dots

Solution steps

3 x^{3} + 7 x^{2} - 33 x - 77 = 0

Factor

3 x^{3} + 7 x^{2} - 33 x - 77 : (3 x + 7) (x + 11) (x - 11)

(3 x + 7) (x + 11) (x - 11) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 7 = 0 or x + 11 = 0 or x - 11 = 0

Solve

3 x + 7 = 0 : x = - \frac{7}{3}

Solve

x + 11 = 0 : x = - 11

Solve

x - 11 = 0 : x = 11

The solutions are

x = - \frac{7}{3}, x = - 11, x = 11

9 x^{4} + 49 = 58 x^{2}

16 r^{4} + 24 r^{2} + 9 = 0

x^{3} - 125 x^{2} + 3842 x - 16129 = 0

x, x^{3} = 6 y

x^{3} + 3 x^{2} - 45 x + 81 = 0

What are the solutions to the equation 3x^3+7x^2-33x-77=0 ?
The solutions to the equation 3x^3+7x^2-33x-77=0 are x=-7/3 ,x=-sqrt(11),x=sqrt(11)
Find the zeros of 3x^3+7x^2-33x-77=0
The zeros of 3x^3+7x^2-33x-77=0 are x=-7/3 ,x=-sqrt(11),x=sqrt(11)