What are the solutions to the equation x^2+(7/25)^2=1 ?

The solutions to the equation x^2+(7/25)^2=1 are x= 24/25 ,x=-24/25

Find the zeros of x^2+(7/25)^2=1

The zeros of x^2+(7/25)^2=1 are x= 24/25 ,x=-24/25

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x^{2} + (\frac{7}{25})^{2} = 1

x = \frac{24}{25}, x = - \frac{24}{25}

Decimal Notation

x = 0.96, x = - 0.96

Solution steps

x^{2} + (\frac{7}{25})^{2} = 1

Expand

x^{2} + (\frac{7}{25})^{2} : x^{2} + \frac{49}{625}

x^{2} + \frac{49}{625} = 1

Move

\frac{49}{625}

to the right side

x^{2} = 1 - \frac{49}{625}

Simplify

1 - \frac{49}{625} : \frac{576}{625}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{576}{625}, x = - \frac{576}{625}

\frac{576}{625} = \frac{24}{25}

- \frac{576}{625} = - \frac{24}{25}

x = \frac{24}{25}, x = - \frac{24}{25}

0 = 3 x^{2} - 10 x

3 \geq 3

4 x + 8 \leq - 3 x - 5

5 \geq 2 p + 1

10 (23 + 7) = 100 l + 100 l

What are the solutions to the equation x^2+(7/25)^2=1 ?
The solutions to the equation x^2+(7/25)^2=1 are x= 24/25 ,x=-24/25
Find the zeros of x^2+(7/25)^2=1
The zeros of x^2+(7/25)^2=1 are x= 24/25 ,x=-24/25