What are the solutions to the equation x^3-3x=x ?

The solutions to the equation x^3-3x=x are x=0,x=-2,x=2

Find the zeros of x^3-3x=x

The zeros of x^3-3x=x are x=0,x=-2,x=2

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x^{3} - 3 x = x

x = 0, x = - 2, x = 2

Solution steps

x^{3} - 3 x = x

Move

x

to the left side

x^{3} - 4 x = 0

Factor

x^{3} - 4 x : x (x + 2) (x - 2)

x (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 2 = 0 or x - 2 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = - 2, x = 2

y, x = (y + 2)^{3}

x, f = x^{2} y g x^{2} + 2

x^{3} \cdot (2 \cdot x - 6) = 0

k^{3} - 3 k^{2} - 0.47 k + 0.47 = 0

4 \cdot 1 0^{- 9} = 4 x^{3}

What are the solutions to the equation x^3-3x=x ?
The solutions to the equation x^3-3x=x are x=0,x=-2,x=2
Find the zeros of x^3-3x=x
The zeros of x^3-3x=x are x=0,x=-2,x=2