What are the solutions to the equation 0.024=(1+x/(12))^{12}-1 ?

The solutions to the equation 0.024=(1+x/(12))^{12}-1 are x=0.02373…,x=-24.02373…

Find the zeros of 0.024=(1+x/(12))^{12}-1

The zeros of 0.024=(1+x/(12))^{12}-1 are x=0.02373…,x=-24.02373…

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0.024 = (1 + \frac{x}{12})^{12} - 1

x = 0.02373 \dots, x = - 24.02373 \dots

Solution steps

0.024 = (1 + \frac{x}{12})^{12} - 1

Switch sides

(1 + \frac{x}{12})^{12} - 1 = 0.024

Move

1

to the right side

(1 + \frac{x}{12})^{12} = 1.024

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x = 0.02373 \dots, x = - 24.02373 \dots

x^{6} - 11 x^{3} + 30 = 0

x^{3} - 6 x^{2} - 7 x = 0

x^{4} - 5 x^{2} - 8 = 0

x^{5} (x + 1) (x - 1) = 0

y^{4} + 21 y^{2} - 100 = 0

What are the solutions to the equation 0.024=(1+x/(12))^{12}-1 ?
The solutions to the equation 0.024=(1+x/(12))^{12}-1 are x=0.02373…,x=-24.02373…
Find the zeros of 0.024=(1+x/(12))^{12}-1
The zeros of 0.024=(1+x/(12))^{12}-1 are x=0.02373…,x=-24.02373…