What are the solutions to the equation 4x^3-7x^2+66x+17=0 ?

The solutions to the equation 4x^3-7x^2+66x+17=0 are x=-1/4 ,x=1+4i,x=1-4i

Find the zeros of 4x^3-7x^2+66x+17=0

The zeros of 4x^3-7x^2+66x+17=0 are x=-1/4 ,x=1+4i,x=1-4i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{3} - 7 x^{2} + 66 x + 17 = 0

x = - \frac{1}{4}, x = 1 + 4 i, x = 1 - 4 i

Solution steps

4 x^{3} - 7 x^{2} + 66 x + 17 = 0

Factor

4 x^{3} - 7 x^{2} + 66 x + 17 : (4 x + 1) (x^{2} - 2 x + 17)

(4 x + 1) (x^{2} - 2 x + 17) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x + 1 = 0 or x^{2} - 2 x + 17 = 0

Solve

4 x + 1 = 0 : x = - \frac{1}{4}

Solve

x^{2} - 2 x + 17 = 0 : x = 1 + 4 i, x = 1 - 4 i

The solutions are

x = - \frac{1}{4}, x = 1 + 4 i, x = 1 - 4 i

- 30 x = - 6 x^{3} + 5 x

x^{4} - 8 x^{2} + 5 = 5

0 = x - x^{3}

x^{3} - 7 x^{2} + 12 x - 6 = 0

384 = 3 h \cdot 2 h \cdot h

What are the solutions to the equation 4x^3-7x^2+66x+17=0 ?
The solutions to the equation 4x^3-7x^2+66x+17=0 are x=-1/4 ,x=1+4i,x=1-4i
Find the zeros of 4x^3-7x^2+66x+17=0
The zeros of 4x^3-7x^2+66x+17=0 are x=-1/4 ,x=1+4i,x=1-4i