What are the solutions to the equation -5x^3+11x^2-4x-2=0 ?

The solutions to the equation -5x^3+11x^2-4x-2=0 are x=1,x=(3+sqrt(19))/5 ,x=(3-sqrt(19))/5

Find the zeros of -5x^3+11x^2-4x-2=0

The zeros of -5x^3+11x^2-4x-2=0 are x=1,x=(3+sqrt(19))/5 ,x=(3-sqrt(19))/5

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- 5 x^{3} + 11 x^{2} - 4 x - 2 = 0

x = 1, x = \frac{3 + 19}{5}, x = \frac{3 - 19}{5}

Decimal Notation

x = 1, x = 1.47177 \dots, x = - 0.27177 \dots

Solution steps

- 5 x^{3} + 11 x^{2} - 4 x - 2 = 0

Factor

- 5 x^{3} + 11 x^{2} - 4 x - 2 : - (x - 1) (5 x^{2} - 6 x - 2)

- (x - 1) (5 x^{2} - 6 x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 5 x^{2} - 6 x - 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

5 x^{2} - 6 x - 2 = 0 : x = \frac{3 + 19}{5}, x = \frac{3 - 19}{5}

The solutions are

x = 1, x = \frac{3 + 19}{5}, x = \frac{3 - 19}{5}

x, x^{3} - 3 x^{3} y = 0

x^{3} + x^{2} - 13 x - 21 = 0

mm (m + 2) (m + 3) = 7

35 x^{4} = x^{4}

x^{4} = 6 x^{2} - 5

What are the solutions to the equation -5x^3+11x^2-4x-2=0 ?
The solutions to the equation -5x^3+11x^2-4x-2=0 are x=1,x=(3+sqrt(19))/5 ,x=(3-sqrt(19))/5
Find the zeros of -5x^3+11x^2-4x-2=0
The zeros of -5x^3+11x^2-4x-2=0 are x=1,x=(3+sqrt(19))/5 ,x=(3-sqrt(19))/5