What are the solutions to the equation (x^3-27)=0 ?

The solutions to the equation (x^3-27)=0 are x=3,x=-3/2+(3sqrt(3))/2 i,x=-3/2-(3sqrt(3))/2 i

Find the zeros of (x^3-27)=0

The zeros of (x^3-27)=0 are x=3,x=-3/2+(3sqrt(3))/2 i,x=-3/2-(3sqrt(3))/2 i

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(x^{3} - 27) = 0

x = 3, x = - \frac{3}{2} + \frac{3 3}{2} i, x = - \frac{3}{2} - \frac{3 3}{2} i

Solution steps

(x^{3} - 27) = 0

x^{3} - 27 = 0

Move

27

to the right side

x^{3} = 27

For

x^{3} = f (a)

the solutions are

Simplify

x = 3, x = - \frac{3}{2} + \frac{3 3}{2} i, x = - \frac{3}{2} - \frac{3 3}{2} i

x^{2} (x - 1) (x + 6) = 0

x^{3} + 5 x^{2} + 12 x + 8 = 0

x^{2} (x^{2} - 16) - 25 (x^{2} - 16) = 0

x^{3} + x^{2} + x + 6 = 0

x^{5} = x^{3}

What are the solutions to the equation (x^3-27)=0 ?
The solutions to the equation (x^3-27)=0 are x=3,x=-3/2+(3sqrt(3))/2 i,x=-3/2-(3sqrt(3))/2 i
Find the zeros of (x^3-27)=0
The zeros of (x^3-27)=0 are x=3,x=-3/2+(3sqrt(3))/2 i,x=-3/2-(3sqrt(3))/2 i