What are the solutions to the equation 2x^5-x+1=0 ?

The solutions to the equation 2x^5-x+1=0 are x=-1

Find the zeros of 2x^5-x+1=0

The zeros of 2x^5-x+1=0 are x=-1

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2 x^{5} - x + 1 = 0

x = - 1

Solution steps

2 x^{5} - x + 1 = 0

Factor

2 x^{5} - x + 1 : (x + 1) (2 x^{4} - 2 x^{3} + 2 x^{2} - 2 x + 1)

(x + 1) (2 x^{4} - 2 x^{3} + 2 x^{2} - 2 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or 2 x^{4} - 2 x^{3} + 2 x^{2} - 2 x + 1 = 0

Solve

x + 1 = 0 : x = - 1

Solve

2 x^{4} - 2 x^{3} + 2 x^{2} - 2 x + 1 = 0 :

No Solution for

x \in R

The solution is

x = - 1

(3 x^{2} - 13 x + 14) (x^{2} - 4 x + 1) = 0

y, x = (y + 7)^{3}

r^{3} + 3 r^{2} - 9 r - 27 = 0

v^{3} = 343

x, 6 y - 12 x^{3} = 0

What are the solutions to the equation 2x^5-x+1=0 ?
The solutions to the equation 2x^5-x+1=0 are x=-1
Find the zeros of 2x^5-x+1=0
The zeros of 2x^5-x+1=0 are x=-1