What are the solutions to the equation x^3+2x^2+21x-58=0 ?

The solutions to the equation x^3+2x^2+21x-58=0 are x=2,x=-2+5i,x=-2-5i

Find the zeros of x^3+2x^2+21x-58=0

The zeros of x^3+2x^2+21x-58=0 are x=2,x=-2+5i,x=-2-5i

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x^{3} + 2 x^{2} + 21 x - 58 = 0

x = 2, x = - 2 + 5 i, x = - 2 - 5 i

Solution steps

x^{3} + 2 x^{2} + 21 x - 58 = 0

Factor

x^{3} + 2 x^{2} + 21 x - 58 : (x - 2) (x^{2} + 4 x + 29)

(x - 2) (x^{2} + 4 x + 29) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x^{2} + 4 x + 29 = 0

Solve

x - 2 = 0 : x = 2

Solve

x^{2} + 4 x + 29 = 0 : x = - 2 + 5 i, x = - 2 - 5 i

The solutions are

x = 2, x = - 2 + 5 i, x = - 2 - 5 i

n^{3} = n^{1} - n^{2}

0 = x^{4} - 3 x^{3} + 3 x^{2}

x^{10} + x^{5} + 1 = 0

y^{3} - 25 y^{2} - 178 y + 1165 = 0

x^{4} - 52 x^{2} + 147 = 0

What are the solutions to the equation x^3+2x^2+21x-58=0 ?
The solutions to the equation x^3+2x^2+21x-58=0 are x=2,x=-2+5i,x=-2-5i
Find the zeros of x^3+2x^2+21x-58=0
The zeros of x^3+2x^2+21x-58=0 are x=2,x=-2+5i,x=-2-5i