What are the solutions to the equation 34-7x(8-3)=34-7x^8+7x^3 ?

The solutions to the equation 34-7x(8-3)=34-7x^8+7x^3 are x=0,x\approx 1.31289…

Find the zeros of 34-7x(8-3)=34-7x^8+7x^3

The zeros of 34-7x(8-3)=34-7x^8+7x^3 are x=0,x\approx 1.31289…

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34 - 7 x (8 - 3) = 34 - 7 x^{8} + 7 x^{3}

x = 0, x \approx 1.31289 \dots

Solution steps

34 - 7 x (8 - 3) = 34 - 7 x^{8} + 7 x^{3}

Expand

34 - 7 x (8 - 3) : 34 - 35 x

34 - 35 x = 34 - 7 x^{8} + 7 x^{3}

Switch sides

34 - 7 x^{8} + 7 x^{3} = 34 - 35 x

Move

34

to the right side

- 7 x^{8} + 7 x^{3} = - 35 x

Move

35 x

to the left side

- 7 x^{8} + 7 x^{3} + 35 x = 0

Factor

- 7 x^{8} + 7 x^{3} + 35 x : - 7 x (x^{7} - x^{2} - 5)

- 7 x (x^{7} - x^{2} - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{7} - x^{2} - 5 = 0

Solve

x^{7} - x^{2} - 5 = 0 : x \approx 1.31289 \dots

The solutions are

x = 0, x \approx 1.31289 \dots

1.64 x^{40} = 0.082 x^{284} x D

r^{3} + r^{2} + r + 1 = 0

4 x^{4} - 17 x^{2} + 3 = 0

a^{2} = a^{4}

(u + 9)^{3} = - (u + 9)^{2}

What are the solutions to the equation 34-7x(8-3)=34-7x^8+7x^3 ?
The solutions to the equation 34-7x(8-3)=34-7x^8+7x^3 are x=0,x\approx 1.31289…
Find the zeros of 34-7x(8-3)=34-7x^8+7x^3
The zeros of 34-7x(8-3)=34-7x^8+7x^3 are x=0,x\approx 1.31289…