What are the solutions to the equation 12^2+x^2=17^2 ?

The solutions to the equation 12^2+x^2=17^2 are x=sqrt(145),x=-sqrt(145)

Find the zeros of 12^2+x^2=17^2

The zeros of 12^2+x^2=17^2 are x=sqrt(145),x=-sqrt(145)

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1 2^{2} + x^{2} = 1 7^{2}

x = 145, x = - 145

Decimal Notation

x = 12.04159 \dots, x = - 12.04159 \dots

Solution steps

1 2^{2} + x^{2} = 1 7^{2}

Move

1 2^{2}

to the right side

x^{2} = 145

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 145, x = - 145

\frac{5 x - 2}{3} - \frac{2 - x}{3} > - 1

- \frac{5}{9} + (- \frac{7}{12})

0.2 5^{\frac{1}{3}}

x (x - 2) + 12 = (x + 1) (x + 2)

k - 4 = - 24

What are the solutions to the equation 12^2+x^2=17^2 ?
The solutions to the equation 12^2+x^2=17^2 are x=sqrt(145),x=-sqrt(145)
Find the zeros of 12^2+x^2=17^2
The zeros of 12^2+x^2=17^2 are x=sqrt(145),x=-sqrt(145)