What are the solutions to the equation X^3+3X^2-4X-12=0 ?

The solutions to the equation X^3+3X^2-4X-12=0 are X=-3,X=-2,X=2

Find the zeros of X^3+3X^2-4X-12=0

The zeros of X^3+3X^2-4X-12=0 are X=-3,X=-2,X=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

X^{3} + 3 X^{2} - 4 X - 12 = 0

X = - 3, X = - 2, X = 2

Solution steps

X^{3} + 3 X^{2} - 4 X - 12 = 0

Factor

X^{3} + 3 X^{2} - 4 X - 12 : (X + 3) (X + 2) (X - 2)

(X + 3) (X + 2) (X - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

X + 3 = 0 or X + 2 = 0 or X - 2 = 0

Solve

X + 3 = 0 : X = - 3

Solve

X + 2 = 0 : X = - 2

Solve

X - 2 = 0 : X = 2

The solutions are

X = - 3, X = - 2, X = 2

x^{5} - x^{3} - 3 x - 2 = 0

x^{3} - 15 = - 7

0 = x^{3} - x^{2} - 7 x + 7

(2 a - 1)^{4} - 1 = 0

a^{3} - a = 0

What are the solutions to the equation X^3+3X^2-4X-12=0 ?
The solutions to the equation X^3+3X^2-4X-12=0 are X=-3,X=-2,X=2
Find the zeros of X^3+3X^2-4X-12=0
The zeros of X^3+3X^2-4X-12=0 are X=-3,X=-2,X=2