What are the solutions to the equation -2(9x+4)(x^2+25)=0 ?

The solutions to the equation -2(9x+4)(x^2+25)=0 are x=-4/9 ,x=5i,x=-5i

Find the zeros of -2(9x+4)(x^2+25)=0

The zeros of -2(9x+4)(x^2+25)=0 are x=-4/9 ,x=5i,x=-5i

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- 2 (9 x + 4) (x^{2} + 25) = 0

x = - \frac{4}{9}, x = 5 i, x = - 5 i

Solution steps

- 2 (9 x + 4) (x^{2} + 25) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

9 x + 4 = 0 or x^{2} + 25 = 0

Solve

9 x + 4 = 0 : x = - \frac{4}{9}

Solve

x^{2} + 25 = 0 : x = 5 i, x = - 5 i

The solutions are

x = - \frac{4}{9}, x = 5 i, x = - 5 i

2 = (1 + x)^{6}

x^{3} + x^{2} - 2 x + 2 = 0

x^{6} - x - 1 = 0

a^{3} + (1 - a)^{2} - 1 = 0

x^{3} - 2 x^{4} = 13

What are the solutions to the equation -2(9x+4)(x^2+25)=0 ?
The solutions to the equation -2(9x+4)(x^2+25)=0 are x=-4/9 ,x=5i,x=-5i
Find the zeros of -2(9x+4)(x^2+25)=0
The zeros of -2(9x+4)(x^2+25)=0 are x=-4/9 ,x=5i,x=-5i