What are the solutions to the equation 4x^3-2x^2+x+7=0 ?

The solutions to the equation 4x^3-2x^2+x+7=0 are x=-1,x= 3/4+i(sqrt(19))/4 ,x= 3/4-i(sqrt(19))/4

Find the zeros of 4x^3-2x^2+x+7=0

The zeros of 4x^3-2x^2+x+7=0 are x=-1,x= 3/4+i(sqrt(19))/4 ,x= 3/4-i(sqrt(19))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{3} - 2 x^{2} + x + 7 = 0

x = - 1, x = \frac{3}{4} + i \frac{19}{4}, x = \frac{3}{4} - i \frac{19}{4}

Solution steps

4 x^{3} - 2 x^{2} + x + 7 = 0

Factor

4 x^{3} - 2 x^{2} + x + 7 : (x + 1) (4 x^{2} - 6 x + 7)

(x + 1) (4 x^{2} - 6 x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or 4 x^{2} - 6 x + 7 = 0

Solve

x + 1 = 0 : x = - 1

Solve

4 x^{2} - 6 x + 7 = 0 : x = \frac{3}{4} + i \frac{19}{4}, x = \frac{3}{4} - i \frac{19}{4}

The solutions are

x = - 1, x = \frac{3}{4} + i \frac{19}{4}, x = \frac{3}{4} - i \frac{19}{4}

- x^{5} + 16 x = 0

0 = x^{3} + 4 x^{2} - x - 4

x^{8} - 2 x^{6} + 2 x^{4} - 2 x^{2} + 1 = 0

x^{3} + 4 x^{2} - 21 x = 0

z^{4} + 4 \cdot z^{2} - 45 = 0

What are the solutions to the equation 4x^3-2x^2+x+7=0 ?
The solutions to the equation 4x^3-2x^2+x+7=0 are x=-1,x= 3/4+i(sqrt(19))/4 ,x= 3/4-i(sqrt(19))/4
Find the zeros of 4x^3-2x^2+x+7=0
The zeros of 4x^3-2x^2+x+7=0 are x=-1,x= 3/4+i(sqrt(19))/4 ,x= 3/4-i(sqrt(19))/4