What are the solutions to the equation 6p^2+10p+2=p^2 ?

The solutions to the equation 6p^2+10p+2=p^2 are p=(-5+sqrt(15))/5 ,p=-(5+sqrt(15))/5

Find the zeros of 6p^2+10p+2=p^2

The zeros of 6p^2+10p+2=p^2 are p=(-5+sqrt(15))/5 ,p=-(5+sqrt(15))/5

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6 p^{2} + 10 p + 2 = p^{2}

p = \frac{- 5 + 15}{5}, p = - \frac{5 + 15}{5}

Solution steps

6 p^{2} + 10 p + 2 = p^{2}

Move

p^{2}

to the left side

5 p^{2} + 10 p + 2 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 5 \cdot 2}{2 \cdot 5}

1 0^{2} - 4 \cdot 5 \cdot 2 = 215

p_{1, 2} = \frac{- 10 \pm 2 15}{2 \cdot 5}

Separate the solutions

p_{1} = \frac{- 10 + 2 15}{2 \cdot 5}, p_{2} = \frac{- 10 - 2 15}{2 \cdot 5}

p = \frac{- 10 + 2 15}{2 \cdot 5} : \frac{- 5 + 15}{5}

p = \frac{- 10 - 2 15}{2 \cdot 5} : - \frac{5 + 15}{5}

The solutions to the quadratic equation are:

p = \frac{- 5 + 15}{5}, p = - \frac{5 + 15}{5}

14 > - 2 x + 6 > - 2

y^{0}

(x + 8) (x - 3)^{2} (x - 7)^{3} < 0

- 12 + 3 b - 1 = - 5 - b

- (- 5)^{2}

What are the solutions to the equation 6p^2+10p+2=p^2 ?
The solutions to the equation 6p^2+10p+2=p^2 are p=(-5+sqrt(15))/5 ,p=-(5+sqrt(15))/5
Find the zeros of 6p^2+10p+2=p^2
The zeros of 6p^2+10p+2=p^2 are p=(-5+sqrt(15))/5 ,p=-(5+sqrt(15))/5