What are the solutions to the equation 6x^3-5x^2-2x+1=0 ?

The solutions to the equation 6x^3-5x^2-2x+1=0 are x=1,x= 1/3 ,x=-1/2

Find the zeros of 6x^3-5x^2-2x+1=0

The zeros of 6x^3-5x^2-2x+1=0 are x=1,x= 1/3 ,x=-1/2

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6 x^{3} - 5 x^{2} - 2 x + 1 = 0

x = 1, x = \frac{1}{3}, x = - \frac{1}{2}

Decimal Notation

x = 1, x = 0.33333 \dots, x = - 0.5

Solution steps

6 x^{3} - 5 x^{2} - 2 x + 1 = 0

Factor

6 x^{3} - 5 x^{2} - 2 x + 1 : (x - 1) (3 x - 1) (2 x + 1)

(x - 1) (3 x - 1) (2 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 3 x - 1 = 0 or 2 x + 1 = 0

Solve

x - 1 = 0 : x = 1

Solve

3 x - 1 = 0 : x = \frac{1}{3}

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

The solutions are

x = 1, x = \frac{1}{3}, x = - \frac{1}{2}

4 x^{3} = 36 - x

x^{8} + 2 x^{6} - x^{4} - 2 x^{2} + 1 = 0

2 x^{3} + 1 = 55

2 x (x - 8) (3 x - 2) = 0

x^{4} + 5 x^{3} + 5 x^{2} + 5 x + 2 = 0

What are the solutions to the equation 6x^3-5x^2-2x+1=0 ?
The solutions to the equation 6x^3-5x^2-2x+1=0 are x=1,x= 1/3 ,x=-1/2
Find the zeros of 6x^3-5x^2-2x+1=0
The zeros of 6x^3-5x^2-2x+1=0 are x=1,x= 1/3 ,x=-1/2